Questions
The P-V diagram of 4 gm of helium gas for a certain process is shown in the figure. what is the heat given to the gas during the process
a
4PoVo
b
6PoVo
c
4.5PoVo
d
2PoVo
detailed solution
Correct option is B
Change in internal energy from A→B is ΔU=f2μRΔT=f2(PfVf−PiVi)=32(2P0×2V0−P0×V0)=92P0V0Work done in process A→B is equal to the Area covered by the graph with volume axis i.e.,WA→B=12(P0+2P0)×(2V0−V0)=32P0V0Hence, ΔQ=ΔU+ΔW =92P0V0+32P0V0=6P0V0Talk to our academic expert!
Similar Questions
Which of the following laws of thermodynamics defines internal energy?
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