The P-V diagram of 4 gm of helium gas for a certain process  A→B is shown in the figure. what is the heat given to the gas during the process   A→B

Change in internal energy from A→B  is ΔU=f2μRΔT=f2(PfVf−PiVi)=32(2P0×2V0−P0×V0)=92P0V0Work done in process  A→B is equal to the Area covered by the graph with volume axis i.e.,WA→B=12(P0+2P0)×(2V0−V0)=32P0V0Hence,  ΔQ=ΔU+ΔW  =92P0V0+32P0V0=6P0V0