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A radio active isotope ${}_{Z}X^{A}$ decays in series by emitting 3 $α$ -particles and two $β^{-}$ particles. The product will be

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Y A-13 Z-3

Z-4YA-12

Z-5YA-11

Z-6YA-11

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detailed solution

Correct option is B

Each α-decay decreases the atomic number by 2 and mass number by 4. Each β--decay increases the atomic number by 1. Hence net atomic number decreases by 4 while net mass number decreases by 12.

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A radio active isotope X A Z decays in series by emitting 3 α -particles and two β- particles. The product will be

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A radio active isotope ${}_{Z}X^{A}$ decays in series by emitting 3 $α$ -particles and two $β^{-}$ particles. The product will be