A radio active isotope X A Z decays in series by emitting 3 α -particles and two β- particles. The product will be
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a
Y A-13 Z-3
b
Z-4YA-12
c
Z-5YA-11
d
Z-6YA-11
answer is B.
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Detailed Solution
Each α-decay decreases the atomic number by 2 and mass number by 4. Each β--decay increases the atomic number by 1. Hence net atomic number decreases by 4 while net mass number decreases by 12.