First slide

Radio activity

Question

A radio active isotope ${}_{Z}X^{A}$ decays in series by emitting 3 $α$ -particles and two $β^{-}$ particles. The product will be

Moderate

A

${}_{Z - 3}Y^{A - 13}$
B

$_{Z - 4} Y^{A - 12}$
C

$_{Z - 5} Y^{A - 11}$
D

$_{Z - 6} Y^{A - 11}$

Solution

Each $α$ -decay decreases the atomic number by 2 and mass number by 4. Each $β^{-}$ -decay increases the atomic number by 1. Hence net atomic number decreases by 4 while net mass number decreases by 12.

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