A radioactive nucleus initially at rest decays by emitting an electron and neutron at right angles to one another. The momentum of the electron is $3.2 \times 10^{- 23}$ kgm/s and the momentum of neutron is 6.4 x $10^{- 23}$ kgm/sec. The direction of the recoiling nucleus with that of the electron motion is:

Question

Infinity Learn · Accepted Answer

Pe $$=$$ $$3.2$$ × $$10-23$$ $$kgm/s$$, Pn $$=$$ $$6.4$$×$$10-23$$ $$kgm/sPR$$ $$=$$ $$Pe2+Pn2$$ $$=$$ (3.2)2+(6.4)2$$×$$10-23$$ $$kgm/stan$$ θ $$=PnPe$$  $$=$$ $$6.4$$×$$10-233.2$$×$$10-23$$ $$=$$ $$2According$$ to law of conservation of momentum, the residual nucleus must move in a direction just opposite to that of PR→, as shown infigure. Hence, direction of the recoiling nucleus with that of the electron motion ∅ $$=$$ π$$-$$θ $$=$$ π$$-$$$$tan$$$$-1(2)..

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A radioactive nucleus initially at rest decays by emitting an electron and neutron at right angles to one another. The momentum of the electron is 3.2 ×10-23 kgm/s and the momentum of neutron is 6.4 x 10-23 kgm/sec. The direction of the recoiling nucleus with that of the electron motion is:

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