A radioactive nucleus undergoes a series of decays according to the scheme
$A \overset{α}{\to} A_{1} \overset{β}{\to} A_{2} \overset{α}{\to} A_{3} \overset{γ}{\to} A_{4}$
If the mass number and atomic number of A are 180 and 72 respectively, then what are these number for $A_{4} ?$

Question

A radioactive nucleus undergoes a series of decays according to the scheme

$A \overset{α}{\to} A_{1} \overset{β}{\to} A_{2} \overset{α}{\to} A_{3} \overset{γ}{\to} A_{4}$

If the mass number and atomic number of A are 180 and 72 respectively, then what are these number for $A_{4} ?$

Infinity Learn · Accepted Answer

Two α$$-particles$$ reduce mass number by $$8$$.∴New mass number $$=$$ $$180$$ — $$8$$ $$=$$ $$172Emission$$ of two α$$-particles$$ reduces charge number by $$4$$. Emission of β $$-particles$$ increases charge number by $$1$$.∴ New charge number $$=$$ $$72$$ — $$4$$ $$+$$ $$1$$ $$=$$ $$69$$.

A radioactive nucleus undergoes a series of decays according to the scheme
$A \overset{α}{\to} A_{1} \overset{β}{\to} A_{2} \overset{α}{\to} A_{3} \overset{γ}{\to} A_{4}$
If the mass number and atomic number of A are 180 and 72 respectively, then what are these number for $A_{4} ?$

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A radioactive nucleus undergoes a series of decays according to the schemeA→αA1→βA2→αA3→γA4If the mass number and atomic number of A are 180 and 72 respectively, then what are these number for A4?

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A radioactive nucleus undergoes a series of decays according to the scheme
$A \overset{α}{\to} A_{1} \overset{β}{\to} A_{2} \overset{α}{\to} A_{3} \overset{γ}{\to} A_{4}$
If the mass number and atomic number of A are 180 and 72 respectively, then what are these number for $A_{4} ?$