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Radius of the nucleus of the atom with $A = 216$ is $(R_{0} = 1.3 f m)$

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detailed solution

Correct option is B

A=216 R0=1.3fm R=R0(A)13=1.3×(216)13 =1.3×6=7.8fm

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Radius of the nucleus of the atom with A=216 is (R0=1.3 fm)

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Radius of the nucleus of the atom with $A = 216$ is $(R_{0} = 1.3 f m)$