Questions
The ratio of longest wavelength and the shortest wavelength observed in the fifth spectral series of emission spectrum of hydrogen is
detailed solution
Correct option is D
Shortest wavelength comes from n1=∞ to n2=1 and longest wavelength comes from n1= 6 to n2= 5 in thegiven case. Hence 1λmin=R112−1∞2=R1λmax=R152−162=R36−2525×36=11900R∴λmaxλmin=90011Talk to our academic expert!
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