Questions
A reversible engine converts one-sixth of the heat input into work. When the temperature of the sink is reduced by , the efficiency of the engine is doubled. The temperatures of the source and sink are
detailed solution
Correct option is D
Initially η = (1-T2T1) = WQ = 16--------------(i)Finally η' = (1-T2'T1) = (1-(T2-62)T1) = 1-T2T1+62T1 = η+62T1---------------(ii)It is given that η' = 2η. Hence solving equations (i) and (ii)⇒ T1 = 372 K = 990C and T2 = 310 K = 370CTalk to our academic expert!
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