The root mean square velocity of the molecules in a sample of helium is(5/7) times the root mean square velocity of the molecules in a sample of hydrogen at temperature 0oC The temperature of helium is
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a
234oC
b
6oC
c
273oC
d
100oC
answer is B.
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Detailed Solution
VHe = 57VH2;TH2=0oCTo find THe=? We Know that Vrms=3RTMVHeVH2=57 3RTHeMHexMH23RTH2=57 3RxTHe MHe xMH23RTH2=2549 THe 4x2273.15=2549 THe =25x2x273.1549=278.72 K =(278.72-273.15)oC =5.57oC≅6oC