For the same raise in temperature of two moles of gas at constant pressure, the heat required for triatomic gas is K times the heat required for monoatomic gas. The value of K is
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a
32
b
52
c
83
d
85
answer is D.
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Detailed Solution
molar specific heat of gas at constant pressure for tri atomic gas (6° of freedom)Cp=4R molar specific heat of gas at constant pressure is Cp Cp=52R for monoatomic gasheat required for raise in temperature of gas at constant pressure is Q=nCp∆TQtriatomic=kQmonotomic substitute the valuesn(4R)∆T=kn(5R2)∆T ∴K=4R52R=85Heat required is 85 times.