A square loop ABCD carrying a current i,is placed near and coplanar with a long straight conductor XY carrying a current I, the net force on the loop will be

Force on arm AB due to current in conductor XY is F1=μ04π2IiL(L/2)=μ0Iiπacting towards X Y in the plane of loop. Force on arm CD due to current in conductor X Y isF2=μ04π2IiL3(L/2)=μ0Ii3πacting away from X Y in the plane of loop.therefore Net force on the loop =F1-F2=μ0Iiπ1-13=23μ0Iiπ