Questions
A system absorbs 1000 cal of heat and does 1675 J of external work. If J = 4.18 J/cal, then the change in internal energy of the system is
a
+1675 J
b
+2505 J
c
+1000 J
d
+650J
detailed solution
Correct option is B
ΔU=Q−W=(1000×4.18−1675)J=2505JTalk to our academic expert!
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Which of the following laws of thermodynamics defines internal energy?
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