First slide

Questions on calorimetry without phase change

Question

The temperature of equal masses of three different liquids A,B and C are12°C, 19°C and 28° C respectively. The temperature when A and B are mixed is 16°C and when B and C are mixed is 23°C. The temperature when A and C are mixed is:

Moderate

A

19.6°C
B

22°C
C

20.2°C
D

24.2°C

Solution

$m_{1} s_{1} (θ_{1} - θ) = m_{2} s_{2} (θ - θ_{2}) s_{1} (16 - 12) = s_{2} (19 - 16) s_{1} = \frac{3}{4} s_{2} m_{2} s_{2} (θ' - θ_{2}) = m_{3} s_{3} (θ_{3} - θ') s_{2} (23 - 19) = s_{3} (28 - 23) s_{3} = \frac{4}{5} s_{2} m_{1} s_{1} (θ - 12) = m_{3} s_{3} (28 - θ) \frac{3}{4} s_{2} (θ - 12) = \frac{4}{5} s_{2} (28 - θ) θ = 20 . 2^{0} C$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App