First slide

Heat ;work and internal energy

Question

The temperature of 5 mol of a gas which was held at constant volume was Changed from 100⁰C to 120⁰C. The change in internal energy was found to be 80J The total heat capacity of the gas at constant volume will be equal to

Moderate

A

$8 J K^{- 1}$
B

$4 J K^{- 1}$
C

$0.4 J K^{- 1}$
D

$0.8 J K^{- 1}$

Solution

At constant volume the total energy will be utilized in increasing the temperature of gas
$i . e ., Δ Q = μ C_{V} Δ T$
$μ C_{V} = \frac{Δ Q}{Δ T} = \frac{80}{20} = 4 J / k$

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