The temperature-entropy diagram of a reversible engine cycle is given in fig. Its efficiency is
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a
2/3
b
1/3
c
1/4
d
1/2
answer is B.
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Detailed Solution
We know that change in entropy ∆S is given by ΔS=ΔQT or ΔQ=TΔSFor calculation of Q1 and Q2, see fig.Here, Q1=T0S0+12T0S0=32T0S0Q2=T0S0 and Q3=0Now, η=WQ1=Q1−Q2Q1=1−Q2Q1=1−23=13