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In a thermodynamic process helium gas obeys the law Tp25=constant.The heat given to the gas when temperature of m moles of gas is raised from T to 2T is:

a
8 RT
b
4 RT
c
16 RT
d
zero

detailed solution

Correct option is D

Using     PV=RT and TP25=constant, we get PV53=constant,i.e., Process is adiabatic and so Q=0.

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