Questions
In a thermodynamic process pressure of a fixed mass of a gas is changed in such a manner that the gas molecules give out 30 J of heat and 10 J of work is done on the gas. If the internal energy of the gas was 40 J, then the internal energy wiII be
detailed solution
Correct option is B
Here dQ = d + dWdU=Uf−Ui∴ dQ=Uf−Ui+dWor Uf=dQ+Ui−dWdQ=−30J(heat is rejected by system) Ui=40J and dW=−10J∴ Uf=−30+40+10=20JTalk to our academic expert!
Similar Questions
Which of the following laws of thermodynamics defines internal energy?
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
