In a thermodynamic process pressure of a fixed mass of a gas is changed in such a manner that the gas molecules give out 30 J of heat and 10 J of work is done on the gas. If the internal energy of the gas was 40 J, then the internal energy wiII be
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a
-20 J
b
20 J
c
80 J
d
30 J
answer is B.
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Detailed Solution
Here dQ = d + dWdU=Uf−Ui∴ dQ=Uf−Ui+dWor Uf=dQ+Ui−dWdQ=−30J(heat is rejected by system) Ui=40J and dW=−10J∴ Uf=−30+40+10=20J
In a thermodynamic process pressure of a fixed mass of a gas is changed in such a manner that the gas molecules give out 30 J of heat and 10 J of work is done on the gas. If the internal energy of the gas was 40 J, then the internal energy wiII be