A thermodynamical process is shown in the figure (4). The pressures and volumes corresponding to some points in the fig. (4) are
$\begin{aligned} P_{A} = 3 \times 10^{4} {PaV}_{A} = 2 \times 10^{- 3} m^{3} \\ P_{D} = 8 \times 10^{4} {PaV}_{D} = 5 \times 10^{- 3} m^{3} \end{aligned}$
In the process AB,600 J of heat is added to the system and in process 8C,200 | of heat is added to the system. The change in internal energy of the system in process
AC would be

Question

A thermodynamical process is shown in the figure (4). The pressures and volumes corresponding to some points in the fig. (4) are

$\begin{aligned} P_{A} = 3 \times 10^{4} {PaV}_{A} = 2 \times 10^{- 3} m^{3} \\ P_{D} = 8 \times 10^{4} {PaV}_{D} = 5 \times 10^{- 3} m^{3} \end{aligned}$
In the process AB,600 J of heat is added to the system and in process 8C,200 | of heat is added to the system. The change in internal energy of the system in process
AC would be

Infinity Learn · Accepted Answer

For process AB, Δ$$Q=$$Δ$$U+$$Δ$$W=UB$$−$$UA+dW$$∴ $$600=UB$$−$$UA+0$$ or UB−$$UA=600For$$ process BC,Δ$$Q=$$Δ$$U+dW200=UC$$−$$UB+PBVC$$−$$VB=UC$$−$$UB+8$$×$$1045$$×$$10$$−$$3$$−$$2$$×$$10$$−$$3=UC$$−$$UB+240$$∴ UC−$$UB=200$$−$$240=$$−$$40JFor$$ process AC,Change in internal $$energy=UC$$−$$UA=UC$$−$$UB+UB$$−$$UA=$$−$$40+600=560J$$

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