Download the app

Questions  

Three perfect gases at absolute temperatures T1,  T2    and   T3 are mixed. The masses  of the molecules are  m1,  m2andm3 and number of molecules are n1,  n2andn3  respectively. Assuming no loss of energy, the final temperature of the mixture is

a
T1+T2+T33
b
n1T1+n2T2+n3T3n1+n2+n3
c
n1T12+n2T22+n3T32n1T1+n2T2+n3T3
d
n12T12+n22T22+n32T32n1T1+n2T2+n3T3

detailed solution

Correct option is B

Let  T3>T2>T1 and final temperature be T such that T3>T>T2>T1 .Heat lost by first two gases is equal to heat gained by third gasn1CT−T1+n2CT−T2=n1CT3−T⇒T=n1T1+n2T2+n3T3n1+n2+n3

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A jar has a mixture of hydrogen and oxygen gas in the ratio of 1 : 5. The ratio of mean kinetic energies of hydrogen and oxygen molecules is


phone icon
whats app icon