Questions
Three perfect gases at absolute temperatures are mixed. The masses of the molecules are and number of molecules are respectively. Assuming no loss of energy, the final temperature of the mixture is
detailed solution
Correct option is B
Let T3>T2>T1 and final temperature be T such that T3>T>T2>T1 .Heat lost by first two gases is equal to heat gained by third gasn1CT−T1+n2CT−T2=n1CT3−T⇒T=n1T1+n2T2+n3T3n1+n2+n3Talk to our academic expert!
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