The time period of revolution of electron in its ground state orbit in a hydrogen atom is 1.6×10−16 s. The frequency of revolution of the electron in its first excited state in s−1 is
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a
7.8×1014
b
5.6×1012
c
6.2×1015
d
1.6×1014
answer is A.
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Detailed Solution
We know Time Period , T∝rv∝n2z×nz∝n3z2 ⇒T1T2=n13n23=18 ⇒T2=8T1 =8×1.6×10−16=12.8×10−16Now, frequency, f2=1T2=112.8×10−16≈7.8×1014