Download the app

Questions  

The time period of revolution of electron in its ground state orbit in a hydrogen atom is 1.6×1016 s. The frequency of revolution of the electron in its first excited state ins1 is

a
7.8×1014
b
5.6×1012
c
6.2×1015
d
1.6×1014

detailed solution

Correct option is A

We know Time Period , T∝rv∝n2z×nz∝n3z2               ​⇒T1T2=n13n23=18  ⇒T2=8T1 =8×1.6×10−16=12.8×10−16​Now, frequency, f2=1T2=112.8×10−16≈7.8×1014

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

In the following atoms and moleculates for the transition from n= 2  to n = 1, the spectral line of minimum wavelength will be produced by


phone icon
whats app icon