First slide

Bohr's atom model

Question

The total energy of an electron in the ground state of hydrogen atom is -13.6 eV. The potential energy of an electron in the ground state of Li²⁺ ion will be

Moderate

A

122.4 eV
B

-122.4 eV
C

244.8 eV
D

-244.8 eV

Solution

$E_{p} = - \frac{k e^{2}}{r}, E = - \frac{k e^{2}}{2 r}$
$So, E_{p} = 2 E = 2 (- 13.6) eV = - 27.2 eV$
Potential energy of electron in the ground state of Li²⁺ ion is
$- 3^{2} \times 27.2 eV or - 244.8 eV$

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