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Q.

16 tuning forks are arranged in the order of increasing frequencies. Any two successive forks give 8 beats per sec when sounded together. If the frequency of the last fork is twice the first, then the frequency of the first fork is (in Hz)

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a

120

b

160

c

180

d

220

answer is A.

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Detailed Solution

Using nLast = nFirst + (N – 1)x⇒ 2n = n + (16 – 1) × 8 ⇒ n = 120 Hz

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16 tuning forks are arranged in the order of increasing frequencies. Any two successive forks give 8 beats per sec when sounded together. If the frequency of the last fork is twice the first, then the frequency of the first fork is (in Hz)