Two different gases are enclosed in two different identical chambers maintained at common temperature. Their pressures are $$P1$$ and $$P2$$ respectively. The two chambers are connected by a thin pipe keeping the temperature same. Then final pressure is (assuming$$ adiabatic $$walls)

Question

Two different gases are enclosed in two different identical chambers maintained at common temperature. Their pressures are  $$P1$$ and  $$P2$$ respectively. The two chambers are connected by a thin pipe keeping the temperature same. Then final pressure is (assuming$$ adiabatic $$walls)

Infinity Learn · Accepted Answer

Process is isothermal for each gas. Each gas occupies twice the volume it occupied originally. Hence, pressure of each gas halves. New pressures are  $$P12$$ and $$P22$$  respectively. Hence, total pressure, by Dalton’s law, $$=$$ $$P1+P22$$ .

Two different gases are enclosed in two different identical chambers maintained at common temperature. Their pressures are P₁ and P₂ respectively. The two chambers are connected by a thin pipe keeping the temperature same. Then final pressure is (assuming adiabatic walls)

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Two different gases are enclosed in two different identical chambers maintained at common temperature. Their pressures are P1 and P2 respectively. The two chambers are connected by a thin pipe keeping the temperature same. Then final pressure is (assuming adiabatic walls)

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Two different gases are enclosed in two different identical chambers maintained at common temperature. Their pressures are P₁ and P₂ respectively. The two chambers are connected by a thin pipe keeping the temperature same. Then final pressure is (assuming adiabatic walls)