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Q.

Two identical containers A and B with frictionless pistons contain the same ideal gas at the same temperature and the same volume. The mass of the gas in ‘A’ is mA and that in B is mB . The gas in each cylinder is now allowed to expand isothermal to the same final volume 2v. The change in the pressure in A and B are found to be ΔP and 1.5ΔP respectively. Then

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a

2mA=3mB

b

4mA=9mB

c

9mA=3mB

d

3mA=2mB

answer is D.

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Detailed Solution

In isothermal process P∝1VIn chamber A : ΔP=Pi−Pf=μARTV-μART2V=μART2V--(1)In chamber B : 1.5ΔP=Pi−Pf=μBRTV-μBRT2V=μBRT2V---(2)divide 1 by 2 we get From equal A and B μAμB=11.5=23mA/MmB/M=23→3mA=2mB

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