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Questions  

Two identical containers A and B with frictionless pistons contain the same ideal gas at the same temperature and the same volume. The mass of the gas in ‘A’ is  mA and that in B is mB . The gas in each cylinder is now allowed to expand isothermal to the same final volume 2v. The change in the pressure in A and B are found to be  ΔP and  1.5ΔP respectively. Then
 

a
2mA=3mB
b
4mA=9mB
c
9mA=3mB
d
3mA=2mB

detailed solution

Correct option is D

In isothermal process  P∝1VIn chamber A :  ΔP=Pi−Pf=μARTV-μART2V=μART2V--(1)In chamber B :  1.5ΔP=Pi−Pf=μBRTV-μBRT2V=μBRT2V---(2)divide 1 by 2 we get From equal   A and B  μAμB=11.5=23mA/MmB/M=23→3mA=2mB

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