First slide
Questions on calorimetry without phase change
Question

Two liquids of equal volume are thoroughly mixed. If their specific heats are C1,C2 temperatures θ1,θ2 and densities d1, d2 respectively, the final temperature of the mixture is: 

Moderate
Solution

Heat lost = Heat gained 
          Vd1C1(θ-θ1)=Vd2C2(θ2-θ)                                  θ=d1C1θ1+d2C2θ2d1C1+d2C2

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