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Q.

Two liquids of equal volume are thoroughly mixed. If their specific heats are C1,C2 temperatures θ1,θ2 and densities d1, d2 respectively, the final temperature of the mixture is:

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a

C1θ1+C2θ2d1C1+d2C2

b

d1C1θ1+d2C2θ2d1C1+d2C2

c

d1C1θ1+d2C2θ2d1θ1+d2θ2

d

d1θ1+d2θ2C1θ1+C2θ2

answer is B.

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Detailed Solution

Heat lost = Heat gained ⇒ Vd1C1(θ-θ1)=Vd2C2(θ2-θ) ⇒ θ=d1C1θ1+d2C2θ2d1C1+d2C2

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Two liquids of equal volume are thoroughly mixed. If their specific heats are C1,C2 temperatures θ1,θ2 and densities d1, d2 respectively, the final temperature of the mixture is: