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Two liquids of equal volume are thoroughly mixed. If their specific heats are $C_{1}, C_{2}$ temperatures $θ_{1}, θ_{2}$ and densities d₁, d₂ respectively, the final temperature of the mixture is:

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C1θ1+C2θ2d1C1+d2C2

d1C1θ1+d2C2θ2d1C1+d2C2

d1C1θ1+d2C2θ2d1θ1+d2θ2

d1θ1+d2θ2C1θ1+C2θ2

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detailed solution

Correct option is B

Heat lost = Heat gained ⇒ Vd1C1(θ-θ1)=Vd2C2(θ2-θ) ⇒ θ=d1C1θ1+d2C2θ2d1C1+d2C2

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Two liquids of equal volume are thoroughly mixed. If their specific heats are C1,C2 temperatures θ1,θ2 and densities d1, d2 respectively, the final temperature of the mixture is:

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Two liquids of equal volume are thoroughly mixed. If their specific heats are $C_{1}, C_{2}$ temperatures $θ_{1}, θ_{2}$ and densities d₁, d₂ respectively, the final temperature of the mixture is: