First slide

Questions on calorimetry without phase change

Question

Two liquids at temperatures 60^oC and 20^oC respectively have masses in the ratio 3 : 4 and their specific heats in the ratio 4 : 5. If the two liquids are mixed, the resultant temperature is

Easy

A

70^oC
B

50^oC
C

40^oC
D

35^oC

Solution

$\large m_1s_1(60-t)=m_2s_2(t-20)$
$\large \frac 34\frac 45(60-t)=t-20;t=35^oC$

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