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Q.

Two moles of an ideal gas with CPCV=53  are mixed with 3 moles of another ideal gas with  CPCV=43. The values of  CPCV for the mixture is

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a

1.50

b

1.42

c

1.47

d

1.45

answer is B.

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Detailed Solution

γmixture=n1CP1+n2CP2n1CV1+n2CV2=n1γ1Rγ1−1+n2γ2Rγ2−1n1Rγ1−1+n2Rγ2−1​After rearranging we get, n1+n2γmix−1=n1γ1−1+n2γ2−1​⇒5γmix−1=31/3+22/3 ⇒5γmix−1=9+3=12​⇒γmixure=1+512=1712⇒γmix=1.42
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