Two paper screens A and B are separated by 150 m. A bullet pierces A and then B. The hole in B is 15 cm below the hole on screen A. If the bullet is travelling horizontally at the time of hitting A, then the velocity of the bullet at A is : (Take g = 10 ms-2)

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1003ms−1

2003ms−1

3003ms−1

5003ms−1

answer is D.

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Detailed Solution

Range = 150 = ut andh=15100=12gt2 or t2=2100×15g=301000 or t=310 ∴u=150t=150×103=5003ms−1

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