Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Two rigid boxes containing different ideal gases are placed on a table. Box A contains one mole of nitrogen at temperature To, while Box B contains one mole of helium at temperature (7/3) T0. The boxes are then put into thermal contact with each other and heat flows between them until the gases reach a common final temperature (ignore the heat capacity of boxes). Then, the final temperature of the gases T1 , in terms of T0 is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

Tf=73T0

b

Tf=32T0

c

Tf=52T0

d

Tf=37T0

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

When two gases are mixed together, thenHeat lost by the helium gas = Heat gained by the nitrogen gasnB×cvHe×73T0−Tf=nA×cvN2×Tf−T0       Box A      1 mole N2  Temperature = T0              Box B      1 mole He  Temperature = 73T0 ⇒ 1×32R×73T0−Tf=1×52R×Tf−T0By solving, we getTf=32T0
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon