First slide
Types of collision
Question

Two steel spheres approach each other headon with the same speed and collide elastically. After the collision one of the sphere's of radius r comes to rest. The radius of the other sphere is

Difficult
Solution

v2 = 0
 

\large \frac{{2{m_1}{u_1}}}{{{m_1} + {m_2}}} - \left( {\frac{{{m_2} - {m_1}}}{{{m_1} + {m_2}}}} \right){u_2} = 0
\large \frac{{2{m_1}v}}{{{m_1} + {m_2}}} = \left( {\frac{{{m_2} - {m_1}}}{{{m_1} + {m_2}}}} \right)v\
\large 3{m_1} = {m_2} \Rightarrow {m_1} = \frac{{{m_2}}}{3}



Alternative Method:
m1v1 + m2 x 0 = m1u + m2(-u)
⇒ m1v1 = (m1 - m2)u.........(1)
 

\large \frac {0-v_1}{+u-(-u)}=e=1\Rightarrow v_1=-2u...(2)


From (1) and (2), 3m1 = m2
 

\large \therefore 3\left ( \frac 43\pi R^3\rho \right )=\frac 43\pi r^3.\rho\Rightarrow R=\frac {r}{(3)^{1/3}}


 

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