Questions
Two vessels A and B contain ideal gases with the temperature of B double that of A. Both gases are heated, so that they attain the same temperature. It is found that the fractional increase in the most probable speed of gas in vessel ,A is double that of the mean speed of gas in B. The ratio of the final to the initial temperature of gas in vessell is
detailed solution
Correct option is C
EA = 32kTA; EB = 32k(2TA)and EA' = 32kT; EB' = 32kT∆vpvp= (TTA-1) = 2∆vavgvavg = 2(T2TA-1)Let TTA = x, the above equation reduces to(x -1) = 2(x2-1) or x(2-1) = 1or x = [1(3-22)]or x = 3 + 22Talk to our academic expert!
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If the mean free path of atoms of an ideal gas at pressure P is doubled, then the pressure of gas will become
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