First slide

Measurement

Question

A vernier calliper has 1 mm mark on the main scale. It has 20 equal divisions on the vernier scale which match with 16 main scale divisions. For this vernier callipers, the least count is

Moderate

A

0.02 mm
B

0.05 mm
C

0.1 mm
D

0.2 mm

Solution

Least count of a vernier calliper,
LC =1MSD – 1 VSD
20 divisions of Vernier scale =16 divisions of main scale
$1 V S D = \frac{16}{20} m m = 0.8 m m$
$∴$ LC =1MSD–1VSD
=1mm–0.8mm
= 0.2mm

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