First slide

Thermometry

Question

A vessel is filled with an ideal gas at a pressure of 20 atm and is at a temperature of 27°C. One half of the mass of the gas is removed from the vessel and the temperature of the remaining gas is increased to 87°C. At this temperature the pressure of the gas will be

Easy

A

80 atm
B

8.3atm
C

12atm
D

0.12atm

Solution

We have $\large PV=\frac mM RT$ , V₂ = V₁ = constant.
$\large P\propto mT;\;\frac {P_2}{P_1}=\frac {m_2}{m_1}\frac {T_2}{T_1}\Rightarrow \frac { P_2}{20}=\frac 12.\frac {360}{300}$
$\large \therefore P_2=12atm$

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