First slide

Bohr's atom model

Question

The wavelength of radiation required to excite the electron from the first orbit to the third orbit in a doubly ionized lithium atom will be

Moderate

A

134.25 $Å$
B

125.5 $Å$
C

113.7 $Å$
D

110 $Å$

Solution

$\begin{array}{rcl} Required energy & = & [(\frac{- 13.6}{9}) - (\frac{- 13.6}{1})] \times 9 (∵ E = \frac{- 13.6 z^{2}}{n^{2}}) \\ = & [13.6 - \frac{13.6}{9}] 9 = 8 \times 13.6 eV \\ Wavelength & = & \frac{12375}{8 \times 13.6} = 113.7 Å (∵ E = \frac{12375}{λ Å} e v) \end{array}$

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