we have two wires A and B of the same mass and the same material. The diameter of the wire A is half of that B. If the resistance of wire A is 24 ohm. then the resistance of wire B will be
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a
12 ohm
b
3.0 ohm
c
1.5 ohm
d
none of the above
answer is C.
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Detailed Solution
Same mass, same material, i.e., volume is the same or Al = constantAlso, R=ρlA⇒R1R2= l1l2 × A2A1= A2A12=d2d14⇒ 24R2 = dd/24 =16 ⇒ R1 = 1.5 Ω
we have two wires A and B of the same mass and the same material. The diameter of the wire A is half of that B. If the resistance of wire A is 24 ohm. then the resistance of wire B will be