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we have two wires A and B of the same mass and the same material. The diameter of the wire A is half of that B. If the resistance of wire A is 24 ohm. then the resistance of wire B will be

a
12 ohm
b
3.0 ohm
c
1.5 ohm
d
none of the above

detailed solution

Correct option is C

Same mass, same material, i.e., volume is the same or Al = constantAlso,  R=ρlA⇒R1R2=  l1l2 ×  A2A1= A2A12=d2d14⇒    24R2  =  dd/24  =16  ⇒  R1  =  1.5  Ω

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