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Q.

When the amount of work done is 333 cal and change in internal energy is 167 cal, then the heat supplied is

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a

166 cal

b

333 cal

c

500 cal

d

400 cal

answer is C.

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Detailed Solution

ΔQ=ΔU+ΔW=167+333=500 cal
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When the amount of work done is 333 cal and change in internal energy is 167 cal, then the heat supplied is