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When an electron jumps from $n_{1} t h$ orbit to $n_{2} t h$ orbit, the energy radiated is given by

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hv=E1/E2

hv=E2/E1

hv=E1−E2

hv=E2−E1

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detailed solution

Correct option is C

This is Bohr's Postulate. The energy of emitted photon is difference of the total energies of the two involved orbits. Hence, as per question, n1th is higher orbit. Therefore, hv=E1−E2

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When an electron jumps from n1th orbit to n2th orbit, the energy radiated is given by

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When an electron jumps from $n_{1} t h$ orbit to $n_{2} t h$ orbit, the energy radiated is given by