When hydrogen atom absorbs a photon of wavelength 60 nm, photo-ionization of atom occurs. The maximum kinetic energy of emitted electron will be
13.6 eV
7'15 eV
3'6 eV
1'9 eV
The energy of photon of wavelength of 60 nm will be=hcλ=6⋅64×10−343×10860×10−91⋅6×10−9eV=20⋅75eV We know that binding energy of electron in ll-atom = 13.6 eV . K.E. of emitted electron = zo.7s-t3-6 = 7.15eV