Questions
When hydrogen atom absorbs a photon of wavelength 60 nm, photo-ionization of atom occurs. The maximum kinetic energy of emitted electron will be
detailed solution
Correct option is B
The energy of photon of wavelength of 60 nm will be=hcλ=6⋅64×10−343×10860×10−91⋅6×10−9eV=20⋅75eV We know that binding energy of electron in ll-atom = 13.6 eV . K.E. of emitted electron = zo.7s-t3-6 = 7.15eVTalk to our academic expert!
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