Questions
At which of the following temperatures would the molecules of a gas have twice the average kinetic energy they have at ?
detailed solution
Correct option is C
E ∝ T ∴ E2E1 = T2T1 ⇒ 2E1E1 = T2(20+273)⇒ T2 = 293 ×2 = 586 K = 3130CTalk to our academic expert!
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