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How many unpaired electrons are present in ${Ni}^{2 +} (Z = 28)$ ?

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Correct option is B

The electronic configuration of ${_{2}}^{{Ni}^{2 +}} (electron = 26)$ is $(1 s)^{2} (2 s)^{2} (2 p)^{6} (3 s)^{2} (3 p)^{6} (3 d)^{8}$ .

Nickel has two unpaired electrons in the 3d sublevel. When nickel ionizes to the +2 state it loses the two electrons in the 4s, so there are still two unpaired electrons in ${Ni}^{2 +}$ . Option B is correct.

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How many unpaired electrons are present in Ni2+(Z=28)?