The van’t Hoff factor for 0.1M Barium nitrate is 2.74. The percentage of dissociation of barium nitrate is

  1. A

    91.3%

  2. B

    87%

  3. C

    100%

  4. D

    74%

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    Solution:

    BaNO32Ba+2+2NO3 Number of ions produced =3=ni=2.74,α=i1n1×100α=2.74131=0.87( or )87%

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