MathematicsThe diagonals of a rhombus are 24 cm and 32 cm then its perimeter is

The diagonals of a rhombus are 24 cm and 32 cm then its perimeter is

$4 A B^{2} = A C^{2} + B D^{2}$

$\Rightarrow 4 A B^{2} = 24^{2} + 32^{2}$

$\Rightarrow A B^{2} = \frac{576 + 1024}{4}$

$\Rightarrow A B^{2} = \frac{1600}{4}$

$\Rightarrow A B = 20 cm$

Perimeter (Rhombus) $= 4 \times 20$

$= 80 cm$

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