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The x-t graph of a particle undergoing simple harmonic motion is shown below. The equation of the particle is given by

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x = 1 \sin (\frac{π}{2} t)

y = 1 \sin (\frac{π}{2} t)

y = 8 \sin (\frac{π}{4} t)

x = 1 \sin (\frac{π}{4} t)

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detailed solution

Correct option is D

The equation of simple harmonic motion is given by $x = A \sin (ω t + ϕ)$ . Using the value of A = 1 cm and $ω = \frac{2 π}{T} = \frac{2 π}{8} = \frac{π}{4}$ , we get $x = 1 \sin (\frac{π}{4} t)$

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