Atomic mass of He and Ne are 4 and 20 amu respectively. The value of the de Broglie wavelength of He gas -73°C is “M” times that of the de-Broglie wavelength of Ne at 727°C. M is
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answer is 5.
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Detailed Solution
The de-Broglie wavelength of gas molecules is given as, λ=h3mkT where k = Boltzmann constantλHc=MλNch3×4×k×200=Mh3×20×k×1000M=3×20×k×10003×4×k×200=20×10004×200=25=5