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At 200°C,hydrogen molecule have velocity 2.4 × 105 cm s-1. The de Broglie wavelength in this case is approximately
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Correct option is A
λ=hmv=6.6×10−27ergs2NA×2.4×105cms−1 Mass of 1 molecule of H2=26.02×1023=6.6×10−27×6.02×10232×2.4×105=8.27×10−9cm=0.8×10−8cm=0.8Å≈1ÅSimilar Questions
The mass of an electron is m, charge is e and it is accelerated from rest through a potential difference of V volts. The velocity acquired by electron will be
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