Ionic equilibrium

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By Expert Faculty of Sri Chaitanya

Question

If the percentage of $H C O_{3}^{-}$ in the $H_{2} {CO}_{3} - {HCO}_{3}^{-}$ buffer so that to have a neutral solutions is $10 \times x$ the then the value of x is $(K_{a} = 4 \times 10^{- 7})$

Moderate

Solution

$P^{H} = p^{k} O + \log \frac{[s o l t]}{a c i d}$
$7 = 7 - \log (4) + \log \frac{[s a l t]}{[a c i d]}$
$\log 4 = \log [\frac{s a l t}{a c i d}]$
$4 = \frac{s}{a}$
$s + a = 4 + 1 = 5$
$s a l t = \frac{4}{5} \times 100^{20}$
$= 80$
$= 10 \times 8$

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