Questions
Milliequivalent of Ba(OH)2 present in 100 mL solution to have pH = 13, is
a
10-2
b
10
c
0.1
d
0.01
detailed solution
Correct option is B
pH= 13∴ H+=10−13MOH−=10−1M=0.1molL−1Ba(OH)2=0.1N=0.1×100=10 milliequivalentsTalk to our academic expert!
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