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Milliequivalent of Ba(OH)2 present in 100 mL solution to have pH = 13, is

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By Expert Faculty of Sri Chaitanya
a
10-2
b
10
c
0.1
d
0.01
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detailed solution

Correct option is B

pH= 13∴ H+=10−13MOH−=10−1M=0.1molL−1Ba(OH)2=0.1N=0.1×100=10 milliequivalents

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