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Q.

Milliequivalent of Ba(OH)2 present in 100 mL solution to have pH = 13, is

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a

10-2

b

10

c

0.1

d

0.01

answer is B.

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Detailed Solution

pH= 13∴ H+=10−13MOH−=10−1M=0.1molL−1Ba(OH)2=0.1N=0.1×100=10 milliequivalents

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