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Q.

If the radius of the first Bohr orbit is x, then de-Broglie wavelength of the electron in the third orbit is nearly

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a

2πx

b

6πx

c

9x

d

x3

answer is B.

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Detailed Solution

Angular momentum is quantized, hencemvrnnh2πBy Bohr's theory a0=Bohr's radius = xrn=n2a0Z=9a01=9x∴      mv9x=3h2π∴           mv=h6πxBy de-Broglie's equation λ=hmv=hh/6πx=6πx
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