M(OH)x has Ksp=4×10−12 and solubility 1×10−4M. What is the value of X ?
M(OH)x⇌Mx++xOH−Ksp=xx(s)x+14×10−12=xx1×10−4x+1
If x=1, 4×10−12=1×10−42=1×10−8 (Incorrect) If x=2, 4×10−12=221×10−42+1=4×1012 (Correct)