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A five digit number divisible by 3 is to be formed using the digits 0, 1, 2, 3, 4 and 5 without repetition. The total number of ways, this can be done is 

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a
240
b
3125
c
600
d
216

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detailed solution

Correct option is D

As 0+1+2+3+4+5=15, for a five digit number to be divisible by 3 either do not use 0 or 3. When 0 is not used, the number of such numbers is 5! and when 3 is not used, the number of such numbers is 5! -4!∴ Required number of ways =5!+(5!−4!)=216


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