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If 2n+1Pn1:2n1Pn=3:5 then equal to 

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a
4
b
6
c
3
d
8

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detailed solution

Correct option is A

We have, 2n+12n−1Pn−1=35⇒5⋅2n+1Pn−1=3⋅2n−1Pn⇒5⋅(2n+1)!(n+2)!=3(2n−1)!(n−1)!⇒5(2n+1)(2n)(2n−1)!(n+2)(n+1)n(n−1)!=3⋅(2n−1)!(n−1)! ⇒ 10(2n+1)=3(n+2)(n+1)⇒ 3n2−11n−4=0⇒n=4


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